# Relationship between power voltage and amperage drop

### Fundamentals of Electricity - Voltage Drop - Definition Reference Links A parallel circuit is one that has two or more paths for the electricity to flow, the loads are parallel to each other. The sum of the currents through each path is equal to the total current that flows from the source. You may remember from the last section that the voltage drops across a resistor in series. The higher the voltage the more power you have with the same current (Watts ( power) = Volts x Amps. I.e V x 1 Amp = Watts but increase the voltage to . How electrical charge relates to voltage, current, and resistance. a quick way to reference the relationship between voltage, current, resistance, and power. . There is also a decrease in the amount of water that will flow through the hose.

So we open this up. Well, the water's immediately gonna drop straight down. That potential energy is gonna be converted to kinetic energy. And you could look at a certain part of the pipe right over here, right over here.

And you could say, well, how much water is flowing per unit time? And that amount of water that is flowing through the pipe at that point in a specific amount of time, that is analogous to current. Current is the amount of charge, so we could say charge per unit time. Q for charge, and t for time. And intuitively you could say, how much, how much charge flowing, flowing past a point in a circuit, a point in circuit in a, let's say, unit of time, we could think of it as a second.

And so you could also think about it as coulombs per second, charge per unit time. And the idea of resistance is something could just keep that charge from flowing at an arbitrarily high rate. And if we want to go back to our water metaphor, what we could do is, we could introduce something that would impede the water, and that could be a narrowing of the pipe.

And that narrowing of the pipe would be analogous to resistance. So in this situation, once again, I have my vertical water pipe, I have opened it up, and you still would have that potential energy, which is analogous to voltage, and it would be converted to kinetic energy, and you would have a flow of water through that pipe, but now at every point in this pipe, the amount of water that's flowing past at a given moment of time is gonna be lower, because you have literally this bottleneck right over here.

So this narrowing is analogous to resistance.

## Ag Power Web Enhanced Course Materials

How much charge flow impeded, impeded. And the unit here is the ohm, is the ohm, which is denoted with the Greek letter omega. So now that we've defined these things and we have our metaphor, let's actually look at an electric circuit. So first, let me construct a battery.

## Current, Voltage and Resistance

So this is my battery. And the convention is my negative terminal is the shorter line here. So I could say that's the negative terminal, that is the positive terminal. Associated with that battery, I could have some voltage. And just to make this tangible, let's say the voltage is equal to 16 volts across this battery. And so one way to think about it is the potential energy per unit charge, let's say we have electrons here at the negative terminal, the potential energy per coulomb here is 16 volts. These electrons, if they have a path, would go to the positive terminal. And so we can provide a path. Let me draw it like this. At first, I'm gonna not make the path available to the electrons, I'm gonna have an open circuit here. It measures how much energy is released per second in a system. In our battery diagram, the size of both the voltage and the current in the bulb determine how much energy is released. In the diagram above, the light bulb would get brighter as the power, measured in watts, increases. We can calculate the power released in the bulb, and of the electrical system as a whole, by multiplying the voltage by the current.

So, to calculate watts, the following formula is used. How to Calculate with Watts, Amps, Volts, and Ohms If you want to do an electrical calculation involving voltage, current, resistance, or power, reference the formulae circle below. For example, we can calculate the power in watts by referencing the yellow area in the circle. This formulae circle is very useful for many electrical engineering tasks. Keep it handy the next time you are dealing with an electrical system.

• Introduction to circuits and Ohm's law
• Ag Power Web Enhanced Course Materials
• How to Understand Electricity: Watts, Amps, Volts, and Ohms

Below are some example equations that are solved using the formulae. It doesn't matter whether you jerk it upwards in a fraction of a second or take 20 minutes to lift it over the same path. It is the same amount of work. When the opposing force is measured in newtons and when the distance traveled against the opposing force is measured in meters, then the work, measured in joules, is the force times the distance: It turns out that a kilogram is a unit of mass. The force that we think of when we try to lift that parallel push-pull boat anchor is the mass times the acceleration of gravity, which happens to be 9.

When we multiply the number of kilograms by 9. Problem The output transformer for your watt push-pull amp weighs 6.

### Electrical/Electronic - Series Circuits

When holding it in your hands, what is the force of gravity pulling it downward? The force of gravity in newtons is then 3kg 9. The top of your bench is 1. How much work is required to pick up the transformer and place it on the bench? What if the transformer is sitting on the floor in the next room, which is 20 meters away? Solution We determined in the previous problem that the force of gravity on a 6.

The amount of work in joules is then 29N 1. It therefore takes the same amount of work, 35 joules.

### Calculating Electric Power | Ohm's Law | Electronics Textbook

Voltage Opposite charges attract. If we move a negative electron towards another electron we perform work because we are moving against an opposing force. Moving two electrons toward two other electrons requires more work because there is more opposing force.